A solution of 200 mL of 1 M KOH is added to 200 mL of 1 M HCl and the mixture is well shaken. This rise in temperature T1 is noted. The experiment is repeated by using 100 mL of each solution and increase in temperature T2 is again noted. Which of the following is correct?

Question

A solution of 200 mL of 1 M KOH is added to 200 mL of 1 M HCl and the mixture is well shaken. This rise in temperature T1 is noted. The experiment is repeated by using 100 mL of each solution and increase in temperature T2 is again noted. Which of the following is correct? (A) T1=T2 (B) T2 is twice as large as T1 (C) T1 is twice as large as T2 (D) T1 is four times as large as T2

Tardigrade Admin · Accepted Answer

200 mL of 1 M KOH +200 mL of 1 M HCl Number of milliequivalents =200 milliequivalents Total volume =400 mL Heat produced =-(13.7 × 200/1000) kcal =400 T 1 ⇒ T1=-(13.7/1000 × 2) 100 mL 1 M KOH +100 mL 1 M HCl Number of milliequivalents =100 milliequivalents Total volume =200 mL Heat produced =-(13.7 × 100/1000) kcal =200 T 2 Evidently T1=T2

$T_{1} = T_{2}$

$T_{2}$ is twice as large as $T_{1}$

$T_{1}$ is twice as large as $T_{2}$

$T_{1}$ is four times as large as $T_{2}$

Q. A solution of 200mL of 1MKOH is added to 200mL of 1MHCl and the mixture is well shaken. This rise in temperature T1​ is noted. The experiment is repeated by using 100mL of each solution and increase in temperature T2​ is again noted. Which of the following is correct?

T1​=T2​

T2​ is twice as large as T1​

T1​ is twice as large as T2​

T1​ is four times as large as T2​

$T_{1} = T_{2}$

$T_{2}$ is twice as large as $T_{1}$

$T_{1}$ is twice as large as $T_{2}$

$T_{1}$ is four times as large as $T_{2}$