A solution containing 2 g of a non-volatile solute in 20 g of water boils at 373.52 K. The molecular mass of the solute is g mol -1. (Nearest integer) Given, water boils at 373 K , K b for water =0.52 K kg mol -1

Question

A solution containing 2 g of a non-volatile solute in 20 g of water boils at 373.52 K. The molecular mass of the solute is g mol -1. (Nearest integer) Given, water boils at 373 K , K b for water =0.52 K kg mol -1 (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Δ T b =373.52-373 =0.52 Δ T b = Kb ⋅ m 0.52 =0.52 × (2/ text Molar Mass ) × (1/20 × 10-3) Molar Mass =100 g / mol

Q. A solution containing $2 g$ of a non-volatile solute in $20 g$ of water boils at $373.52 K$ . The molecular mass of the solute is ______ $g m o l^{- 1}$ . (Nearest integer)
Given, water boils at $373 K, K_{b}$ for water $= 0.52 K k g m o l^{- 1}$

$Δ T_{b} = 373.52 - 373$
$= 0.52$
$Δ T_{b} = K b \cdot m$
$0.52 = 0.52 \times \frac{2}{Molar Mass} \times \frac{1}{20 \times 1 0 ^{- 3}}$
Molar Mass $= 100 g / m o l$

Q. A solution containing 2g of a non-volatile solute in 20g of water boils at 373.52K. The molecular mass of the solute is ______gmol−1. (Nearest integer) Given, water boils at 373K,Kb​ for water =0.52Kkgmol−1

ΔTb​=373.52−373 =0.52 ΔTb​=Kb⋅m 0.52=0.52× Molar Mass 2​×20×10−31​ Molar Mass =100g/mol

Q. A solution containing $2 g$ of a non-volatile solute in $20 g$ of water boils at $373.52 K$ . The molecular mass of the solute is ______ $g m o l^{- 1}$ . (Nearest integer)
Given, water boils at $373 K, K_{b}$ for water $= 0.52 K k g m o l^{- 1}$

$Δ T_{b} = 373.52 - 373$
$= 0.52$
$Δ T_{b} = K b \cdot m$
$0.52 = 0.52 \times \frac{2}{Molar Mass} \times \frac{1}{20 \times 1 0 ^{- 3}}$
Molar Mass $= 100 g / m o l$