A solid sphere moves on a horizontal surface, performing pure rolling motion, with speed v0. It collides with a smooth vertical wall elastically. the velocity at which it again performs pure rolling, is

Question

A solid sphere moves on a horizontal surface, performing pure rolling motion, with speed v0. It collides with a smooth vertical wall elastically. the velocity at which it again performs pure rolling, is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-uzzi0adonutl.png" /> (A) (2/7)v0 (B) (3/7)v0 (C) (4/7)v0 (D) (3/5)v0

Tardigrade Admin · Accepted Answer

COAM Mv0R-(2/5)Mv0R=(7/5)MvR v=(3/7)v0

Q. A solid sphere moves on a horizontal surface, performing pure rolling motion, with speed $v_{0} .$ It collides with a smooth vertical wall elastically. the velocity at which it again performs pure rolling, is

$\frac{2}{7} v_{0}$

$\frac{3}{7} v_{0}$

$\frac{4}{7} v_{0}$

$\frac{3}{5} v_{0}$

COAM
$M v_{0} R - \frac{2}{5} M v_{0} R = \frac{7}{5} M v R$
$v = \frac{3}{7} v_{0}$

Q. A solid sphere moves on a horizontal surface, performing pure rolling motion, with speed v0​. It collides with a smooth vertical wall elastically. the velocity at which it again performs pure rolling, is

72​v0​

73​v0​

74​v0​

53​v0​