A solid cylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms-1. It collides with a horizontal spring of force constant 200 N m-1. The maximum compression produced in the spring will be

Question

A solid cylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms-1. It collides with a horizontal spring of force constant 200 N m-1. The maximum compression produced in the spring will be (A) 0.5 m (B) 0.6 m (C) 0.7 m (D) 0.2 m

Tardigrade Admin · Accepted Answer

(1/2) mv 2[1+( K 2/ R 2)]=(1/2) kx max 2 Putting m =3 kg , v =4 m / s , ( K 2/ R 2)=1 / 2 (For solid cylinder), k =200 Nm -1 we get x max =0.6 m

Q. A solid cylinder of mass $3 k g$ is rolling on a horizontal surface with velocity $4 m s^{- 1}$ . It collides with a horizontal spring of force constant $200 N m^{- 1}$ . The maximum compression produced in the spring will be

0.5 m

0.6 m

0.7 m

0.2 m

$\frac{1}{2} m v^{2} [1 + \frac{K ^{2}}{R ^{2}}] = \frac{1}{2} k x_{m a x}^{2}$
Putting $m = 3 k g, v = 4 m / s, \frac{K ^{2}}{R ^{2}} = 1/2$
(For solid cylinder), $k = 200 N m^{- 1}$ we get
$x_{m a x} = 0.6 m$

Q. A solid cylinder of mass 3kg is rolling on a horizontal surface with velocity 4ms−1. It collides with a horizontal spring of force constant 200Nm−1. The maximum compression produced in the spring will be