A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle inclination 30°. The centre of mass of cylinder has speed of 4 m/s. The distance travelled by the cylinder on the incline surface will be: (Take g = 10 m/s2)

Question

A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle inclination 30°. The centre of mass of cylinder has speed of 4 m/s. The distance travelled by the cylinder on the incline surface will be: (Take g = 10 m/s2) (A) 2.2 m (B) 1.6 m (C) 1.2 m (D) 2.4 m

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/4ab5ad8f4e064b228452a9a3cb55011e-.png" /> (1/2) mv2 ( 1 + (K2/R2)) = mgh ⇒ 8 ( 1 + (1/2)) = 10 h h = 1.2 m (h/l) = sin 30° l = 2.4 m

Q. A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle inclination 30°. The centre of mass of cylinder has speed of 4 m/s. The distance travelled by the cylinder on the incline surface will be : (Take g = 10 m/s $^{2}$ )

2.2 m

1.6 m

1.2 m

2.4 m

$\frac{1}{2} m v^{2} (1 + \frac{K ^{2}}{R ^{2}}) = m g h$
$\Rightarrow 8 (1 + \frac{1}{2}) = 10 h$
$h = 1.2 m$
$\frac{h}{l} = s in 3 0^{\circ}$
$l = 2.4 m$

Q. A solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle inclination 30°. The centre of mass of cylinder has speed of 4 m/s. The distance travelled by the cylinder on the incline surface will be : (Take g = 10 m/s2)