A solid cylinder has mass M, length L and radius R. The moment of inertia of this cylinder about a generator is

Question

A solid cylinder has mass M, length L and radius R. The moment of inertia of this cylinder about a generator is (A)  M( (L2/12)+(R2/4) )  (B)  (ML2/4)  (C)  (1/2)MR2  (D)  (3/2)MR2

Tardigrade Admin · Accepted Answer

Generator axis of a cylinder is a line lying on it's surface and parallel to axis of cylinder By parallel axis theorem I=(MR2/2)+MR2 I=(3/2)MR2

Q. A solid cylinder has mass M, length L and radius R. The moment of inertia of this cylinder about a generator is

$M (\frac{L ^{2}}{12} + \frac{R ^{2}}{4})$

$\frac{M L ^{2}}{4}$

$\frac{1}{2} M R^{2}$

$\frac{3}{2} M R^{2}$

Generator axis of a cylinder is a line lying on it's surface and parallel to axis of cylinder By parallel axis theorem
$I = \frac{M R ^{2}}{2} + M R^{2}$
$I = \frac{3}{2} M R^{2}$

Q. A solid cylinder has mass M, length L and radius R. The moment of inertia of this cylinder about a generator is

M(12L2​+4R2​)

4ML2​

21​MR2

23​MR2

Generator axis of a cylinder is a line lying on it's surface and parallel to axis of cylinder By parallel axis theorem I=2MR2​+MR2 I=23​MR2

$M (\frac{L ^{2}}{12} + \frac{R ^{2}}{4})$

$\frac{M L ^{2}}{4}$

$\frac{1}{2} M R^{2}$

$\frac{3}{2} M R^{2}$

Generator axis of a cylinder is a line lying on it's surface and parallel to axis of cylinder By parallel axis theorem
$I = \frac{M R ^{2}}{2} + M R^{2}$
$I = \frac{3}{2} M R^{2}$