A solenoid of length 0.6 m has a radius of 2 cm and is made up of 600 turns If it carries a current of 4 A , then the magnitude of the magnetic field inside the solenoid is

Question

A solenoid of length 0.6 m has a radius of 2 cm and is made up of 600 turns If it carries a current of 4 A , then the magnitude of the magnetic field inside the solenoid is (A) 6.024 × 10-3 T (B) 8.024 × 10-3 T (C) 5.024 × 10-3 T (D) 7.024 × 10-3 T

Tardigrade Admin · Accepted Answer

Here, n=(600/0.6)=1000 turns / m, I=4A l=0.6 m, r=0.02 m ∵ (l/r)=30 i.e. l >>r Hence, we can use long solenoid formula, then ∴ B=μ0nI=4π×10-7×103×4=50.24×10-4 =5.024×10-3 T

Q. A solenoid of length $0.6 m$ has a radius of $2 c m$ and is made up of $600$ turns If it carries a current of $4 A$ , then the magnitude of the magnetic field inside the solenoid is

$6.024 \times 1 0^{- 3} T$

$8.024 \times 1 0^{- 3} T$

$5.024 \times 1 0^{- 3} T$

$7.024 \times 1 0^{- 3} T$

Here, $n = \frac{600}{0.6} = 1000$ turns / m, $I = 4 A$
$l = 0.6 m$ , $r = 0.02 m$
$∵ \frac{l}{r} = 30$ i.e. $l >> r$
Hence, we can use long solenoid formula, then
$∴ B = μ_{0} n I = 4 π \times 1 0^{- 7} \times 1 0^{3} \times 4 = 50.24 \times 1 0^{- 4}$
$= 5.024 \times 1 0^{- 3} T$

Q. A solenoid of length 0.6m has a radius of 2cm and is made up of 600 turns If it carries a current of 4A , then the magnitude of the magnetic field inside the solenoid is

6.024×10−3T

8.024×10−3T

5.024×10−3T

7.024×10−3T