A solenoid of length 0.6 m has a radius of 1 cm and is made up of 600 turns. It carries a current of 6 A. What is the magnitude of the magnetic field inside the solenoid?

Question

A solenoid of length 0.6 m has a radius of 1 cm and is made up of 600 turns. It carries a current of 6 A. What is the magnitude of the magnetic field inside the solenoid? (A)  7.54× 10-3T  (B)  10.84× 10-3 T  (C)  4.87× 10-3 T  (D)  2.36× 10-2 T

Tardigrade Admin · Accepted Answer

Given, I=0.6 m r=1 cm N=600 i=6 A ⇒ B text inside =μ0 n i =4 π × 10-7 × (600/0.6) × 6 =4 π × 10-7 × 36 × 103 =7.54 × 10-3 T

Q. A solenoid of length $0.6 m$ has a radius of $1 c m$ and is made up of $600$ turns. It carries a current of $6 A$ . What is the magnitude of the magnetic field inside the solenoid?

$7.54 \times 1 0^{- 3} T$

$10.84 \times 1 0^{- 3} T$

$4.87 \times 1 0^{- 3} T$

$2.36 \times 1 0^{- 2} T$

Given, $I = 0.6 m r = 1 c m$
$N = 600 i = 6 A$
$\Rightarrow B_{inside} = μ_{0} ni$
$= 4 π \times 1 0^{- 7} \times \frac{600}{0.6} \times 6$
$= 4 π \times 1 0^{- 7} \times 36 \times 1 0^{3}$
$= 7.54 \times 1 0^{- 3} T$

Q. A solenoid of length 0.6m has a radius of 1cm and is made up of 600 turns. It carries a current of 6A. What is the magnitude of the magnetic field inside the solenoid?

7.54×10−3T

10.84×10−3T

4.87×10−3T

2.36×10−2T