Question

A solenoid of length $0.6 \,m$ has a radius of $1 \,cm$ and is made up of $600$ turns. It carries a current of $6 \,A$. What is the magnitude of the magnetic field inside the solenoid?

• A. $ 7.54\times 10^{-3}T $
• B. $ 10.84\times 10^{-3}\,\,T $
• C. $ 4.87\times 10^{-3}\,\,T $
• D. $ 2.36\times 10^{-2}\,\,T $

Answer 1

Answer: (A)

Given, $I=0.6 \,m\,\, r=1 \,cm$
$N=600\,\, i=6 A$
$\Rightarrow B_{\text {inside }}=\mu_{0} n i$
$=4 \pi \times 10^{-7} \times \frac{600}{0.6} \times 6$
$=4 \pi \times 10^{-7} \times 36 \times 10^{3}$
$=7.54 \times 10^{-3} T$