A solenoid of 1200 turns is wound uniformly in a single layer on a glass tube 2 m long and 0.2 m in diameter. The magnetic intensity at the center of the solenoid when a current of 2 A flows through it is:

Question

A solenoid of 1200 turns is wound uniformly in a single layer on a glass tube 2 m long and 0.2 m in diameter. The magnetic intensity at the center of the solenoid when a current of 2 A flows through it is: (A) 2.4 × 103 A m -1 (B) 1.2 × 103 A m -1 (C) 1 Am -1 (D) 2.4 × 10-3 A m -1

Tardigrade Admin · Accepted Answer

Magnetic field at centre inside the solenoid is given by B =μ0 nI So magnetic intensity at centre H =( B /μ0)= nI =((1200/2))(2) H =1.2 × 103 Am -1

Q. A solenoid of $1200$ turns is wound uniformly in a single layer on a glass tube $2 m$ long and $0.2 m$ in diameter. The magnetic intensity at the center of the solenoid when a current of $2 A$ flows through it is:

$2.4 \times 1 0^{3} A m^{- 1}$

$1.2 \times 1 0^{3} A m^{- 1}$

$1 A m^{- 1}$

$2.4 \times 1 0^{- 3} A m^{- 1}$

Magnetic field at centre inside the solenoid is given by
$B = μ_{0} n I$
So magnetic intensity at centre
$H = \frac{B}{μ _{0}} = n I = (\frac{1200}{2}) (2)$
$H = 1.2 \times 1 0^{3} A m^{- 1}$

Q. A solenoid of 1200 turns is wound uniformly in a single layer on a glass tube 2m long and 0.2m in diameter. The magnetic intensity at the center of the solenoid when a current of 2A flows through it is:

2.4×103Am−1

1.2×103Am−1

1Am−1

2.4×10−3Am−1