A soft drink was bottled with a partial pressure of CO 2 of 3 bar over the liquid at room temperature. The partial pressure of CO 2 over the solution approaches a value of 30 bar when 44 g of CO 2 is dissolved in 1 kg of water at room temperature. The approximate pH of the soft drink is × 10-1 (First dissociation constant of H 2 CO 3=4.0 × 10-7; log 2=0.3; density of the soft drink .=1 g mL -1)

Question

A soft drink was bottled with a partial pressure of CO 2 of 3 bar over the liquid at room temperature. The partial pressure of CO 2 over the solution approaches a value of 30 bar when 44 g of CO 2 is dissolved in 1 kg of water at room temperature. The approximate pH of the soft drink is × 10-1 (First dissociation constant of H 2 CO 3=4.0 × 10-7; log 2=0.3; density of the soft drink .=1 g mL -1) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

P CO 2= K H × CO 2 (3/30)=( K H ⋅ n CO 2/ K H 1) ⇒ n CO 2-0.1 mol pH =(1/2)( pka 1- log c )=(1/2)(6.4 × 1)=3.7 pH =37 × 10-1

PCO2​​=KH​×CO2​ 303​=KH​1KH​⋅nCO2​​​<br/><br/>⇒nCO2​−0.1​mol pH=21​(pka1​−logc)=21​(6.4×1)=3.7 pH=37×10−1

$P_{C O_{2}} = K_{H} \times C O_{2}$

$\frac{3}{30} = \frac{K _{H} \cdot n _{C O_{2}}}{K _{H} 1} < b r / >< b r / >\Rightarrow n_{C O_{2} - 0.1} m o l$

$p H = \frac{1}{2} (p k a_{1} - lo g c) = \frac{1}{2} (6.4 \times 1) = 3.7$

$p H = 37 \times 1 0^{- 1}$