Question

A sniper fires a rifle bullet into a gasoline tank making a hole $53.0m$ below the surface of gasoline. The tank was sealed at $3.10atm$ . The stored gasoline has a density of $660kg{m}^{-3}$ . The velocity with which gasoline begins to shoot out of the hole is

• A. $27.8m{s}^{-1}$
• B. $41.0m{s}^{-1}$
• C. $9.6m{s}^{-1}$
• D. $19.7m{s}^{-1}$

Answer 1

Answer: (B)

According to Bernoulli's theorem,
$P_B+h\rho g=P_A+\frac{1}{2}\rho v_A^2\left(As{v}_A>>v_B\right)$
$3.10P+53\times 660\times 10=P+\frac{1}{2}\times 660v_A^2$
$\Rightarrow 2.1\times 1.01\times 10^5+3.498\times 10^5=\frac{1}{2}\times 660\times v_A^2$
$\Rightarrow 5.619\times 10^5=\frac{1}{2}\times 660\times v_A^2$
$\therefore v_A=\sqrt{\frac{2\times 5.619\times 10^5}{660}}=41m{s}^{-1}$