A smooth chain of length 2 m is kept on a table such that its length of 60 cm hangs freely from the edge of the table. The total mass of the chain is 4 kg. The work done in pulling the entire chain on the table is, (Take g=10 m / s 2 )

Question

A smooth chain of length 2 m is kept on a table such that its length of 60 cm hangs freely from the edge of the table. The total mass of the chain is 4 kg. The work done in pulling the entire chain on the table is, (Take g=10 m / s 2 ) (A) 3.6 J (B) 2.0 J (C) 12.9 J (D) 6.3 J

Tardigrade Admin · Accepted Answer

Mass of the chain lying freely from the table

= M \frac{1}{L}

< b r / > < b r / >= 4 k g \times \frac{0.6}{2} < b r / >= 1.2 k g < b r / > < b r / >

The distance of center of mass of chain from the table

= \frac{1}{2} \times 0.6 m = 0.3 m

Thus the work done in pulling the chain

= m g h = 1.2 \times 10 \times 0.3 J = 3.6 J

Q. A smooth chain of length 2m is kept on a table such that its length of 60cm hangs freely from the edge of the table. The total mass of the chain is 4kg. The work done in pulling the entire chain on the table is, (Take g=10m/s2 )

3.6 J

2.0 J

12.9 J

6.3 J

Mass of the chain lying freely from the table =ML1​ <br/><br/>=4kg×20.6​<br/>=1.2kg<br/>​<br/> The distance of center of mass of chain from the table =21​×0.6m=0.3m Thus the work done in pulling the chain =mgh=1.2×10×0.3J=3.6J

Q. A smooth chain of length $2 m$ is kept on a table such that its length of $60 c m$ hangs freely from the edge of the table. The total mass of the chain is $4 k g$ . The work done in pulling the entire chain on the table is, (Take $g = 10 m / s^{2}$ )