A small quantity, mass m, of water at a temperature θ (in ° C ) is poured on to a larger mass M of ice which is at its melting point. If c is the specific heat capacity of water and L the specific heat capacity of water and L the specific latent heat of fusion of ice, then the mass of ice melted is given by

Question

A small quantity, mass m, of water at a temperature θ (in ° C ) is poured on to a larger mass M of ice which is at its melting point. If c is the specific heat capacity of water and L the specific heat capacity of water and L the specific latent heat of fusion of ice, then the mass of ice melted is given by (A) (M L/m c θ) (B) (M c θ/L) (C) (m c θ/M L) (D) (m c θ/L)

Tardigrade Admin · Accepted Answer

By the principle of mixture, heat given out by water = heat absorbed by the melted ice ⇒ m c(θ-0)=M L ⇒ M=(m c θ/L)

$\frac{M L}{m c θ}$

$\frac{M c θ}{L}$

$\frac{m c θ}{M L}$

$\frac{m c θ}{L}$

By the principle of mixture, heat given out by water = heat absorbed by the melted ice
$\Rightarrow m c (θ - 0) = M L$
$\Rightarrow M = \frac{m c θ}{L}$

mcθML​

LMcθ​

MLmcθ​

Lmcθ​

By the principle of mixture, heat given out by water = heat absorbed by the melted ice ⇒mc(θ−0)=ML ⇒M=Lmcθ​

$\frac{M L}{m c θ}$

$\frac{M c θ}{L}$

$\frac{m c θ}{M L}$

$\frac{m c θ}{L}$

By the principle of mixture, heat given out by water = heat absorbed by the melted ice
$\Rightarrow m c (θ - 0) = M L$
$\Rightarrow M = \frac{m c θ}{L}$