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Question
Physics
A small particle moves to position 5 hati-2 hatj+ hatk from its initial position 2 hati+3 hatj-4 hatk under the action of force 5 hati+2 hatj+7 hatk N. The value of work done will be J.
Q. A small particle moves to position
5
i
^
−
2
j
^
+
k
^
from its initial position
2
i
^
+
3
j
^
−
4
k
^
under the action of force
5
i
^
+
2
j
^
+
7
k
^
N
. The value of work done will be ________
J
.
727
149
JEE Main
JEE Main 2023
Work, Energy and Power
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Answer:
40
Solution:
W
=
F
⋅
(
r
f
−
r
i
)
=
(
5
i
^
+
2
j
^
+
7
k
^
)
⋅
((
5
i
^
−
2
j
^
+
k
^
)
−
(
2
i
^
+
3
j
^
−
4
k
^
))
W
=
40
J