A small bar magnet has a magnetic moment 1.2 Am 2. The magnetic field at a distance 0.1 m on its axis will be (μ0=4 π × 10-7 T - m / A )

Question

A small bar magnet has a magnetic moment 1.2 Am 2. The magnetic field at a distance 0.1 m on its axis will be (μ0=4 π × 10-7 T - m / A ) (A) 1.2 × 10-4 T (B) 2.4 × 10-4 T (C) 2.4 × 104 T (D) 1.2 × 104 T

Tardigrade Admin · Accepted Answer

B=(μ0/4 π) ⋅ (2 M/d3) ⇒ B=10-7 × (2 × 1.2/(0.1)3) =2.4 × 10-4 T

Q. A small bar magnet has a magnetic moment $1.2 A m^{2}$ . The magnetic field at a distance $0.1 m$ on its axis will be $(μ_{0} = 4 π \times 1 0^{- 7} T - m / A)$

$1.2 \times 1 0^{- 4} T$

$2.4 \times 1 0^{- 4} T$

$2.4 \times 1 0^{4} T$

$1.2 \times 1 0^{4} T$

$B = \frac{μ _{0}}{4 π} \cdot \frac{2 M}{d ^{3}}$
$\Rightarrow B = 1 0^{- 7} \times \frac{2 \times 1.2}{( 0.1 ) ^{3}}$
$= 2.4 \times 1 0^{- 4} T$

Q. A small bar magnet has a magnetic moment 1.2Am2. The magnetic field at a distance 0.1m on its axis will be (μ0​=4π×10−7T−m/A)

1.2×10−4T

2.4×10−4T

2.4×104T

1.2×104T