A small ball of mass m starts at a point A with speed v0 and moves along a frictionless track AB as shown. The track BC has coefficient of friction μ. The ball comes to stop at C after travelling a distance L which is :

Question

A small ball of mass m starts at a point A with speed v0 and moves along a frictionless track AB as shown. The track BC has coefficient of friction μ. The ball comes to stop at C after travelling a distance L which is : (A) (2h/μ) + ( upsilon20/2μ g) (B) (h/μ) + ( upsilon20/2μ g) (C) (h/2μ) + ( upsilon20/μ g) (D) (h/2μ) + ( upsilon20/2μ g)

Tardigrade Admin · Accepted Answer

mgh - μ mgL = 0-(1/2) mv20 μ mgL = mgh +(1/2)mv20 L = (h/μ) + ( upsilon20/2μ g)

Q. A small ball of mass $m$ starts at a point $A$ with speed $v_{0}$ and moves along a frictionless track $A B$ as shown. The track $BC$ has coefficient of friction $μ$ . The ball comes to stop at $C$ after travelling a distance $L$ which is :

$\frac{2 h}{μ} + \frac{υ _{0}^{2}}{2 μg}$

$\frac{h}{μ} + \frac{υ _{0}^{2}}{2 μg}$

$\frac{h}{2 μ} + \frac{υ _{0}^{2}}{μg}$

$\frac{h}{2 μ} + \frac{υ _{0}^{2}}{2 μg}$

$m g h - μ m gL = 0 - \frac{1}{2} m v_{0}^{2}$
$μ m gL = m g h + \frac{1}{2} m v_{0}^{2}$
$L = \frac{h}{μ} + \frac{υ _{0}^{2}}{2 μg}$

Q. A small ball of mass m starts at a point A with speed v0​ and moves along a frictionless track AB as shown. The track BC has coefficient of friction μ. The ball comes to stop at C after travelling a distance L which is :

μ2h​+2μgυ02​​

μh​+2μgυ02​​

2μh​+μgυ02​​

2μh​+2μgυ02​​