A slit of width 12 × 10-7 m is illuminated by light of wavelength 6000 mathringA. The angular width (in degree) of central maximum is approximately ?

Question

A slit of width 12 × 10-7 m is illuminated by light of wavelength 6000 mathringA. The angular width (in degree) of central maximum is approximately ? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Central maximum width =(2 λ/a) =(2 × 6000 × 10-10/12 × 10-7) radian =(2 × 6000 × 10-10/12 × 10-7) × (180°/π) =60°

Q. A slit of width $12 \times 1 0^{- 7} m$ is illuminated by light of wavelength $6000 \overset{˚}{A}$ . The angular width (in degree) of central maximum is approximately ?

Central maximum width $= \frac{2 λ}{a}$
$= \frac{2 \times 6000 \times 1 0 ^{- 10}}{12 \times 1 0 ^{- 7}}$ radian
$= \frac{2 \times 6000 \times 1 0 ^{- 10}}{12 \times 1 0 ^{- 7}} \times \frac{18 0 ^{\circ}}{π}$ $= 6 0^{\circ}$

Q. A slit of width 12×10−7m is illuminated by light of wavelength 6000A˚. The angular width (in degree) of central maximum is approximately ?

Central maximum width =a2λ​ =12×10−72×6000×10−10​ radian =12×10−72×6000×10−10​×π180∘​ =60∘

Q. A slit of width $12 \times 1 0^{- 7} m$ is illuminated by light of wavelength $6000 \overset{˚}{A}$ . The angular width (in degree) of central maximum is approximately ?

Central maximum width $= \frac{2 λ}{a}$
$= \frac{2 \times 6000 \times 1 0 ^{- 10}}{12 \times 1 0 ^{- 7}}$ radian
$= \frac{2 \times 6000 \times 1 0 ^{- 10}}{12 \times 1 0 ^{- 7}} \times \frac{18 0 ^{\circ}}{π}$ $= 6 0^{\circ}$