A single slit of width a is illuminated by violet light of wavelength 400 nm and the width of the diffraction pattern is measured as y. When half of the slit width is covered and illuminated by yellow light of wavelength 600 nm, the width of the diffraction pattern is .

Question

A single slit of width a is illuminated by violet light of wavelength 400 nm and the width of the diffraction pattern is measured as y. When half of the slit width is covered and illuminated by yellow light of wavelength 600 nm, the width of the diffraction pattern is . (A) the pattern vanishes and the width is zero (B) (y/3) (C) 3 y (D) none of these

Tardigrade Admin · Accepted Answer

In simple slit diffraction experiment, width of central maxima y=(2 λ D/d) ∴ (y1/y2) =(λ1/λ2) × (d2/d1) =(400/600) × (d / 2/d)=(1/3) y2 =3y

Q. A single slit of width a is illuminated by violet light of wavelength $400 nm$ and the width of the diffraction pattern is measured as $y$ . When half of the slit width is covered and illuminated by yellow light of wavelength $600 nm$ , the width of the diffraction pattern is .

the pattern vanishes and the width is zero

$\frac{y}{3}$

$3 y$

none of these

In simple slit diffraction experiment, width of central maxima $y = \frac{2 λ D}{d}$
$∴ \frac{y _{1}}{y _{2}} = \frac{λ _{1}}{λ _{2}} \times \frac{d _{2}}{d _{1}}$
$= \frac{400}{600} \times \frac{d /2}{d} = \frac{1}{3}$
$y_{2} = 3 y$

Q. A single slit of width a is illuminated by violet light of wavelength 400nm and the width of the diffraction pattern is measured as y. When half of the slit width is covered and illuminated by yellow light of wavelength 600nm, the width of the diffraction pattern is .