A simple pendulum of time period T is suspended above a large horizontal metal sheet with uniformly distributed positive charge. If the bob is given some negative charge, its time period of oscillation will be

Question

A simple pendulum of time period T is suspended above a large horizontal metal sheet with uniformly distributed positive charge. If the bob is given some negative charge, its time period of oscillation will be (A)  > T (B) < T (C) T (D) proportional to its amplitude

Tardigrade Admin · Accepted Answer

Effective weight m g prime=m g+q E or g prime=(g+(q E/m)) T=2 π √(l/g) As g increases, time period decreases. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/44a6e3f2247668f6c3039f35f01ce560-.png" />

Q. A simple pendulum of time period $T$ is suspended above a large horizontal metal sheet with uniformly distributed positive charge. If the bob is given some negative charge, its time period of oscillation will be

$> T$

$< T$

$T$

proportional to its amplitude

Effective weight $m g^{'} = m g + qE$
or $g^{'} = (g + \frac{qE}{m})$
$T = 2 π \frac{l}{g}$
As $g$ increases, time period decreases.

Q. A simple pendulum of time period T is suspended above a large horizontal metal sheet with uniformly distributed positive charge. If the bob is given some negative charge, its time period of oscillation will be

>T

<T

T

proportional to its amplitude

Effective weight mg′=mg+qE or g′=(g+mqE​) T=2πgl​​ As g increases, time period decreases.

Q. A simple pendulum of time period $T$ is suspended above a large horizontal metal sheet with uniformly distributed positive charge. If the bob is given some negative charge, its time period of oscillation will be

$> T$

$< T$

$T$

Effective weight $m g^{'} = m g + qE$
or $g^{'} = (g + \frac{qE}{m})$
$T = 2 π \frac{l}{g}$
As $g$ increases, time period decreases.