A simple pendulum of length L has mass M and it oscillates freely with amplitude A . At the extreme position, its potential energy is ( g = acceleration due to gravity)

Question

A simple pendulum of length L has mass M and it oscillates freely with amplitude A . At the extreme position, its potential energy is ( g = acceleration due to gravity) (A) (M g A2/2 L) (B)  (M g A/2 L) (C) (M g A2/L) (D) (2 M g A2/L)

Tardigrade Admin · Accepted Answer

Potential energy =(1/2)Mω 2A2 =(1/2)M.(g/L).A2 (∵ ω = √(g/L))

Q. A simple pendulum of length $L$ has mass $M$ and it oscillates freely with amplitude $A$ . At the extreme position, its potential energy is ( $g$ = acceleration due to gravity)

$\frac{M g A ^{2}}{2 L}$

$\frac{M g A}{2 L}$

$\frac{M g A ^{2}}{L}$

$\frac{2 M g A ^{2}}{L}$

Potential energy $= \frac{1}{2} M ω^{2} A^{2}$
$= \frac{1}{2} M . \frac{g}{L} . A^{2} (∵ ω = \frac{g}{L})$

Q. A simple pendulum of length L has mass M and it oscillates freely with amplitude A . At the extreme position, its potential energy is ( g = acceleration due to gravity)

2LMgA2​

2LMgA​

LMgA2​

L2MgA2​