A simple harmonic progressive wave is represented as y = 0.03 sin π(2t - 0.01x) m . At a given instant of time, the phase difference between two particles 25 m apart is

Question

A simple harmonic progressive wave is represented as y = 0.03 sin π(2t - 0.01x) m . At a given instant of time, the phase difference between two particles 25 m apart is (A) π rad (B) (π/2) rad (C) (π/4) rad (D) (π/8) rad

Tardigrade Admin · Accepted Answer

The given equation of SHM wave is y =0.03 sin π(2 t-0.01 x) m =0.03 sin (2 π t-0.01 π x) m Compairing it with general equation, we get y=a sin (ω t-k x) where, k=(2 π/λ) ⇒ λ=200 m The phase difference between two particles is given by Δ φ=k x=(2 π/λ) × x ...(i) Here, x=25 m Substituting the values of x and λ in Eq. (i), we get Δ φ=(2 π/200) × 25=(π/4) rad

Q. A simple harmonic progressive wave is represented as $y = 0.03 s in π (2 t - 0.01 x) m$ . At a given instant of time, the phase difference between two particles $25 m$ apart is

$π$ rad

$\frac{π}{2}$ rad

$\frac{π}{4}$ rad

$\frac{π}{8}$ rad

Q. A simple harmonic progressive wave is represented as y=0.03sinπ(2t−0.01x)m . At a given instant of time, the phase difference between two particles 25m apart is

π rad

2π​ rad

4π​ rad

8π​ rad

Q. A simple harmonic progressive wave is represented as $y = 0.03 s in π (2 t - 0.01 x) m$ . At a given instant of time, the phase difference between two particles $25 m$ apart is

$π$ rad

$\frac{π}{2}$ rad

$\frac{π}{4}$ rad

$\frac{π}{8}$ rad