A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of 1012 / sec. What is the force constant of the bonds connecting one atom with the other ? ( Mole wt. of silver = 108 and Avogadro number = 6.02 × 1023 gm mole-1 )

Question

A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of 1012 / sec. What is the force constant of the bonds connecting one atom with the other ? ( Mole wt. of silver = 108 and Avogadro number = 6.02 × 1023 gm mole-1 ) (A) 6.4 N/m (B) 7.1 N/m (C) 2.2 N/m (D) 5.5 N/m

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/cf65fe70f6b8f1f6db034903988eafa8-.png" /> K x=m a ⇒ a=( K / m ) x T=2 π √(m/K) f=(1/T)=(1/2 π) √(K/m)=1012 =(1/4 π2) × (K/m)=1024 K=4 π2 m × 1024=(4 × 10 × 108 × 10-3/6.02 × 1023) × 1024 =7.1 N / m

Q. A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of 1012/sec. What is the force constant of the bonds connecting one atom with the other ? ( Mole wt. of silver =108 and Avogadro number =6.02×1023gmmole−1 )

6.4 N/m

7.1 N/m

2.2 N/m

5.5 N/m

Kx=ma ⇒a=(K/m)x T=2πKm​​ f=T1​=2π1​mK​​=1012 =4π21​×mK​=1024 K=4π2m×1024=6.02×10234×10×108×10−3​×1024 =7.1N/m

Q. A silver atom in a solid oscillates in simple harmonic motion in some direction with a frequency of $1 0^{12} / sec$ . What is the force constant of the bonds connecting one atom with the other ? ( Mole wt. of silver $= 108$ and Avogadro number $= 6.02 \times 1 0^{23} g m m o l e^{- 1}$ )