A Si specimen is made into p-type semiconductor by doping on an average one indium atom per 6×107silicon atoms. If the number density of atoms in Si be 6×1028/m, the indium atoms per cm3 are

Question

A Si specimen is made into p-type semiconductor by doping on an average one indium atom per 6×107silicon atoms. If the number density of atoms in Si be 6×1028/m, the indium atoms per cm3 are (A) 1012 (B) 1015 (C) 1018 (D) 1020

Tardigrade Admin · Accepted Answer

The doping of one indium atom in silicon semiconductor will produce one acceptor atom in p-type semiconductor.
Now, 1 indium atom has been dopped per

6 \times 1 0^{7}

silicon atoms,
So number density of acceptor atoms in silicon is

= \frac{6 \times 1 0 ^{28}}{6 \times 1 0 ^{7}} = 1 0^{21}

atoms

/ m^{3} = 1 0^{15}

atoms

/ c m^{3}

Q. A Si specimen is made into p-type semiconductor by doping on an average one indium atom per $6 \times 1 0^{7}$ silicon atoms. If the number density of atoms in Si be $6 \times 1 0^{28} / m$ , the indium atoms per $c m^{3}$ are

$1 0^{12}$

$1 0^{15}$

$1 0^{18}$

$1 0^{20}$

Q. A Si specimen is made into p-type semiconductor by doping on an average one indium atom per 6×107silicon atoms. If the number density of atoms in Si be 6×1028/m, the indium atoms per cm3 are

1012

1015

1018

1020

The doping of one indium atom in silicon semiconductor will produce one acceptor atom in p-type semiconductor. Now, 1 indium atom has been dopped per 6×107 silicon atoms, So number density of acceptor atoms in silicon is =6×1076×1028​=1021 atoms /m3=1015 atoms /cm3

Q. A Si specimen is made into p-type semiconductor by doping on an average one indium atom per $6 \times 1 0^{7}$ silicon atoms. If the number density of atoms in Si be $6 \times 1 0^{28} / m$ , the indium atoms per $c m^{3}$ are

$1 0^{12}$

$1 0^{15}$

$1 0^{18}$

$1 0^{20}$