A shot is fired from a point at a distance of 200 m from the foot of a tower 100 m high so that it just passes over it horizontally. The direction of shot with horizontal is

Question

A shot is fired from a point at a distance of 200 m from the foot of a tower 100 m high so that it just passes over it horizontally. The direction of shot with horizontal is (A) 30° (B) 45° (C) 60° (D) 70°

Tardigrade Admin · Accepted Answer

H=100 m , R=2 × 200=400 m tan θ=(4 H/R) ⇒ tan θ=(4 × 100/400)=1 ⇒ θ=45° [∵ (H/R)=( tan θ/4)]

Q. A shot is fired from a point at a distance of $200 m$ from the foot of a tower $100 m$ high so that it just passes over it horizontally. The direction of shot with horizontal is

$3 0^{\circ}$

$4 5^{\circ}$

$6 0^{\circ}$

$7 0^{\circ}$

$H = 100 m, R = 2 \times 200 = 400 m$
$tan θ = \frac{4 H}{R} \Rightarrow tan θ = \frac{4 \times 100}{400} = 1$
$\Rightarrow θ = 4 5^{\circ} [∵ \frac{H}{R} = \frac{t a n θ}{4}]$

Q. A shot is fired from a point at a distance of 200m from the foot of a tower 100m high so that it just passes over it horizontally. The direction of shot with horizontal is

30∘

45∘

60∘

70∘