A ship of mass 3 × 107 k g, initially at rest, is pulled by a force of 5 × 104 N through a distance of 3 m. Assuming that the resistance due to water is negligible, the speed of the ship is

Question

A ship of mass 3 × 107 k g, initially at rest, is pulled by a force of 5 × 104 N through a distance of 3 m. Assuming that the resistance due to water is negligible, the speed of the ship is (A) 1.5 m/s (B) 60 m/s (C) 0.1 m/s (D) 5 m/s

Tardigrade Admin · Accepted Answer

Force, F=m a a=(F/m)=(5 × 104/3 × 107) m / s2 ⇒ a=(5/3) × 10-3 m / s2 Since, v2-u2=2 a s v2-0=2 × (5/3) × 10-3 × 3 v2=10-2 v=0.1 m / s

Q. A ship of mass $3 \times 1 0^{7} k g$ , initially at rest, is pulled by a force of $5 \times 1 0^{4} N$ through a distance of 3 m. Assuming that the resistance due to water is negligible, the speed of the ship is

1.5 m/s

60 m/s

0.1 m/s

5 m/s

Force, $F = ma$
$a = \frac{F}{m} = \frac{5 \times 1 0 ^{4}}{3 \times 1 0 ^{7}} m / s^{2}$
$\Rightarrow a = \frac{5}{3} \times 1 0^{- 3} m / s^{2}$
Since, $v^{2} - u^{2} = 2 a s$
$v^{2} - 0 = 2 \times \frac{5}{3} \times 1 0^{- 3} \times 3$
$v^{2} = 1 0^{- 2} v = 0.1 m / s$

Q. A ship of mass 3×107kg, initially at rest, is pulled by a force of 5×104N through a distance of 3 m. Assuming that the resistance due to water is negligible, the speed of the ship is