A set of 20 tuning forks is arranged in a series of increasing frequencies. If each fork gives 4 beats with respect to the preceding fork and the frequency of the last fork is twice the frequency of the first, then the frequency of last fork is Hz.

Question

A set of 20 tuning forks is arranged in a series of increasing frequencies. If each fork gives 4 beats with respect to the preceding fork and the frequency of the last fork is twice the frequency of the first, then the frequency of last fork is Hz. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

f1=f f2=f+4 f3=f+2 × 4 f4=f+3 × 4 f20=f+19 × 4 f+(19 × 4)=2 × f f=76 Hz . Frequency of last tuning forks =2 f =152 Hz

Q. A set of $20$ tuning forks is arranged in a series of increasing frequencies. If each fork gives $4$ beats with respect to the preceding fork and the frequency of the last fork is twice the frequency of the first, then the frequency of last fork is ____ $Hz$ .

$f_{1} = f$
$f_{2} = f + 4$
$f_{3} = f + 2 \times 4$
$f_{4} = f + 3 \times 4$
$f_{20} = f + 19 \times 4$
$f + (19 \times 4) = 2 \times f$
$f = 76 Hz .$
Frequency of last tuning forks $= 2 f$
$= 152 Hz$

Q. A set of 20 tuning forks is arranged in a series of increasing frequencies. If each fork gives 4 beats with respect to the preceding fork and the frequency of the last fork is twice the frequency of the first, then the frequency of last fork is ____Hz.

f1​=f f2​=f+4 f3​=f+2×4 f4​=f+3×4 f20​=f+19×4 f+(19×4)=2×f f=76Hz. Frequency of last tuning forks =2f =152Hz

Q. A set of $20$ tuning forks is arranged in a series of increasing frequencies. If each fork gives $4$ beats with respect to the preceding fork and the frequency of the last fork is twice the frequency of the first, then the frequency of last fork is ____ $Hz$ .

$f_{1} = f$
$f_{2} = f + 4$
$f_{3} = f + 2 \times 4$
$f_{4} = f + 3 \times 4$
$f_{20} = f + 19 \times 4$
$f + (19 \times 4) = 2 \times f$
$f = 76 Hz .$
Frequency of last tuning forks $= 2 f$
$= 152 Hz$