The number of subsets of the set which contain at most n elements is 2n+1C0+2n+1C1+2n+1C2+....+2n+1Cn=K(say)
We have 2K=2(2n+1C0+2n+1C1+2n+1C2+....+2n+1Cn) =(2n+1C0+2n+1C2n+1)+(2n+1C1+2n+1C2n) +...+(2n+1Cn+2n+1Cn+1)(∵nCr=nCn−r) =2n+1C0+2n+1C1+2n+1C2+....+2n+1C2n+1 =22n+1⇒K=22n