A series LCR circuit driven by 300 V at a frequency of 50 Hz contains a resistance R =3 k Ω, an inductor of inductive reactance XL=250 π Ω and an unknown capacitor. The value of capacitance to maximize the average power should be: (. Take .π2=10)

Question

A series LCR circuit driven by 300 V at a frequency of 50 Hz contains a resistance R =3 k Ω, an inductor of inductive reactance XL=250 π Ω and an unknown capacitor. The value of capacitance to maximize the average power should be: (. Take .π2=10) (A) 4 μ F (B) 25 μ F (C) 400 μ F (D) 40 μ F

Tardigrade Admin · Accepted Answer

For maximum average power XL=XC 250 π=(1/2 π(50) C) C=4 × 10-6

Q. A series LCR circuit driven by $300 V$ at a frequency of $50 Hz$ contains a resistance $R = 3 k Ω$ , an inductor of inductive reactance $X_{L} = 250 π Ω$ and an unknown capacitor. The value of capacitance to maximize the average power should be: $($ Take $π^{2} = 10)$

$4 μ F$

$25 μ F$

$400 μ F$

$40 μ F$

For maximum average power
$X_{L} = X_{C}$
$250 π = \frac{1}{2 π ( 50 ) C}$
$C = 4 \times 1 0^{- 6}$

Q. A series LCR circuit driven by 300V at a frequency of 50Hz contains a resistance R=3kΩ, an inductor of inductive reactance XL​=250πΩ and an unknown capacitor. The value of capacitance to maximize the average power should be: ( Take π2=10)

4μF

25μF

400μF

40μF