Q.
A semi-circular loop of radius 30cm wire carries current 6A. An uniform magnetic field 0.5T is present perpendicular to the plane of the loop. What is the magnitude of force exerted on the wire?
Given, the radius of a circular loop, R=30×10−2m
current, I=6A and magnetic field, B=0.5T.
Force exerted on the wire, F=ILBsinθ ⇒F=6×2×30×10−2×0.5×sin90∘ [∵θ=90∘ and sin90∘=1] ⇒F=1.8N