Q. A segment of DNA has 120 adenine and 120 cytosine bases. The total number of nucleotides present in the segment is

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Solution:

According to Chargaff's rules, the amount of adenine is always equal to that of thymine, and the amount of guanine is always equal to that of cytosine i.e A = T (120) and G = C (120), therefore, the total no. of nucleotides would be 120 x 4 = 480.