A screw gauge with a pitch of 0.3mm and a circular scale with 100 divisions is used to measure the thickness of a thin sheet of steel. What is the thickness of the sheet if main scale reading is 1mm and the 30th division coincides with the main scale line. (There is no zero error)?

Question

A screw gauge with a pitch of 0.3mm and a circular scale with 100 divisions is used to measure the thickness of a thin sheet of steel. What is the thickness of the sheet if main scale reading is 1mm and the 30th division coincides with the main scale line. (There is no zero error)? (A) 1.9mm (B) 1.09mm (C) 1.1mm (D) 1.99mm

Tardigrade Admin · Accepted Answer

Least count =(pitch/ textno.of division on circular scale)=(0 . 3 mm/100)=0.003mm Measured value =1mm+30× 0.003=1.09mm

Q. A screw gauge with a pitch of $0.3 mm$ and a circular scale with $100$ divisions is used to measure the thickness of a thin sheet of steel. What is the thickness of the sheet if main scale reading is $1 mm$ and the $3 0^{t h}$ division coincides with the main scale line. (There is no zero error)?

$1.9 mm$

$1.09 mm$

$1.1 mm$

$1.99 mm$

Least count $= \frac{p i t c h}{no.of division on circular scale} = \frac{0.3 mm}{100} = 0.003 mm$
Measured value $= 1 mm + 30 \times 0.003 = 1.09 mm$

Q. A screw gauge with a pitch of 0.3mm and a circular scale with 100 divisions is used to measure the thickness of a thin sheet of steel. What is the thickness of the sheet if main scale reading is 1mm and the 30th division coincides with the main scale line. (There is no zero error)?

1.9mm

1.09mm

1.1mm

1.99mm

Least count =no.of division on circular scalepitch​=1000.3mm​=0.003mm Measured value =1mm+30×0.003=1.09mm

$1.9 mm$

$1.09 mm$

$1.1 mm$

$1.99 mm$

Least count $= \frac{p i t c h}{no.of division on circular scale} = \frac{0.3 mm}{100} = 0.003 mm$
Measured value $= 1 mm + 30 \times 0.003 = 1.09 mm$