A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is:

Question

A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is: (A) 0.01 mm (B) 0.25 mm (C) 0.5 mm (D) 1.0 mm

Tardigrade Admin · Accepted Answer

L.C. =( textPitch/ textNumber of division on circular scale) ⇒ 0.01 mm=( textpitch/50) ⇒ pitch =0.5 mm

Q. A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale.
The pitch of the screw gauge is:

0.01 mm

0.25 mm

0.5 mm

1.0 mm

L.C. $= \frac{Pitch}{Number of division on circular scale}$
$\Rightarrow 0.01 mm = \frac{pitch}{50}$
$\Rightarrow$ pitch $= 0.5 mm$

Q. A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is: