A screw gauge gives the following reading when used to measure the diameter of a wire. Main scale reading: 0 mm Circular scale reading: 52 division Given that 1 mm on main scale corresponds to 100 divisions of the circular scale. The diameter of the wire from the above data is

Question

A screw gauge gives the following reading when used to measure the diameter of a wire. Main scale reading: 0 mm Circular scale reading: 52 division Given that 1 mm on main scale corresponds to 100 divisions of the circular scale. The diameter of the wire from the above data is (A) 0.52 cm (B) 0.052 cm (C) 0.026 cm (D) 0.005 cm

Tardigrade Admin · Accepted Answer

Least count of screw gauge =(1/100)mm=0.01 mm Diameter = Divisions on circular scale × Least count + main scale reading =52×(1/100)+0 =0.52 mm=0.052 cm

Q. A screw gauge gives the following reading when used to measure the diameter of a wire.
Main scale reading : $0 mm$
Circular scale reading : $52$ division
Given that $1 mm$ on main scale corresponds to $100$ divisions of the circular scale.
The diameter of the wire from the above data is

$0.52 c m$

$0.052 c m$

$0.026 c m$

$0.005 c m$

Least count of screw gauge $= \frac{1}{100} mm = 0.01 mm$
Diameter $=$ Divisions on circular scale $\times$ Least count $+$ main scale reading
$= 52 \times \frac{1}{100} + 0$
$= 0.52 mm = 0.052 c m$

Q. A screw gauge gives the following reading when used to measure the diameter of a wire. Main scale reading : 0mm Circular scale reading : 52 division Given that 1mm on main scale corresponds to 100 divisions of the circular scale. The diameter of the wire from the above data is

0.52cm

0.052cm

0.026cm

0.005cm