A scooter accelerates from rest for time t1 at constant rate a 1 and then retards at constant rate a 2 for time t 2 and comes to rest. The correct value of ( t 1/ t 2) will be :-

Question

A scooter accelerates from rest for time t1 at constant rate a 1 and then retards at constant rate a 2 for time t 2 and comes to rest. The correct value of ( t 1/ t 2) will be :- (A) ( a 1+ a 2/ a 2) (B) ( a 2/ a 1) (C) ( a 1/ a 2) (D) ( a 1+ a 2/ a 1)

Tardigrade Admin · Accepted Answer

Draw vt curve <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/7155f056d0c8009fe155ddbd2c0f4f9c-.png" /> tan θ1= a 1=( v max / t 1) tan θ2= a 2=( v max / t 2) ÷ above ( t 1/ t 2)=( a 2/ a 1)

Q. A scooter accelerates from rest for time $t_{1}$ at constant rate $a_{1}$ and then retards at constant rate $a_{2}$ for time $t_{2}$ and comes to rest. The correct value of $\frac{t _{1}}{t _{2}}$ will be :-

$\frac{a _{1} + a _{2}}{a _{2}}$

$\frac{a _{2}}{a _{1}}$

$\frac{a _{1}}{a _{2}}$

$\frac{a _{1} + a _{2}}{a _{1}}$

Draw $v t$ curve

$tan θ_{1} = a_{1} = \frac{v _{m a x}}{t _{1}}$
$& tan θ_{2} = a_{2} = \frac{v _{m a x}}{t _{2}}$
$\div$ above
$\frac{t _{1}}{t _{2}} = \frac{a _{2}}{a _{1}}$

Q. A scooter accelerates from rest for time t1​ at constant rate a1​ and then retards at constant rate a2​ for time t2​ and comes to rest. The correct value of t2​t1​​ will be :-

a2​a1​+a2​​

a1​a2​​

a2​a1​​

a1​a1​+a2​​