A scientist proposes a new temperature scale in which the ice point is 25 X (X is the new unit of temperature) and the steam point is 305 X. The specific heat capacity of water in this new scale is (in J kg-1 X-1)

Question

A scientist proposes a new temperature scale in which the ice point is 25 X (X is the new unit of temperature) and the steam point is 305 X. The specific heat capacity of water in this new scale is (in J kg-1 X-1) (A) 4.2×103 (B) 3.0×103 (C) 1.2×103 (D) 1.5×103

Tardigrade Admin · Accepted Answer

Given, 305 X -25 X =100° C (∵ X is the new unit of temperature) (305-25) X =100° C ⇒ 280 X =100° C ∴ 1° C =2.8 X The specific heat capacity of water =4200 ( text joule / kg ° C ) =4200 × ( text joule / kg × 2.8 X ) =1500 J / kg - X =1.5 × 103 J kg -1 X -1

Q. A scientist proposes a new temperature scale in which the ice point is $25 X$ ( $X$ is the new unit of temperature) and the steam point is $305 X$ . The specific heat capacity of water in this new scale is (in $J k g^{- 1} X^{- 1}$ )

$4.2 \times 1 0^{3}$

$3.0 \times 1 0^{3}$

$1.2 \times 1 0^{3}$

$1.5 \times 1 0^{3}$

Q. A scientist proposes a new temperature scale in which the ice point is 25X (X is the new unit of temperature) and the steam point is 305X. The specific heat capacity of water in this new scale is (in Jkg−1X−1)

4.2×103

3.0×103

1.2×103

1.5×103

Given, 305X−25X=100∘C (∵X is the new unit of temperature) (305−25)X=100∘C ⇒280X=100∘C ∴1∘C=2.8X The specific heat capacity of water =4200kg∘C joule ​=4200×kg×2.8X joule ​ =1500J/kg−X =1.5×103Jkg−1X−1

Q. A scientist proposes a new temperature scale in which the ice point is $25 X$ ( $X$ is the new unit of temperature) and the steam point is $305 X$ . The specific heat capacity of water in this new scale is (in $J k g^{- 1} X^{- 1}$ )

$4.2 \times 1 0^{3}$

$3.0 \times 1 0^{3}$

$1.2 \times 1 0^{3}$

$1.5 \times 1 0^{3}$