A satellite is revolving round the earth. Its kinetic energy is , How much energy Ek is required by the satellite such that it escapes out of the gravitation field of earth

Question

A satellite is revolving round the earth. Its kinetic energy is , How much energy Ek is required by the satellite such that it escapes out of the gravitation field of earth (A) 2Ek (B) 3Ek (C) (Ek/2) (D) infinity

Tardigrade Admin · Accepted Answer

( E k text esape / E k text rerclutian )=((1/2) mV e 2/(1)2 mV 02)=(( V e / V 0))2=2 E text kescape = E k text reralÙtism (2)=2 E k

Q. A satellite is revolving round the earth. Its kinetic energy is , How much energy $E_{k}$ is required by the satellite such that it escapes out of the gravitation field of earth

$2 E_{k}$

$3 E_{k}$

$\frac{E _{k}}{2}$

infinity

$\frac{E _{k_{esape}}}{E _{k_{rerclutian}}} = \frac{\frac{1}{2} m V _{e}^{2}}{\frac{1}{2} m V _{0}^{2}} = (\frac{V _{e}}{V _{0}})^{2} = 2$
$E_{kescape} = E_{k_{reralيtism}} (2) = 2 E_{k}$

Q. A satellite is revolving round the earth. Its kinetic energy is , How much energy Ek​ is required by the satellite such that it escapes out of the gravitation field of earth

2Ek​

3Ek​

2Ek​​