A sample of a metal oxide has formula M 0.83 O 1.00. The metal M can exist in two oxidation states +2 and +3. In the sample of M 0.83 O 1.00, the percentage of metal ions existing in +2 oxidation state is %. (nearest integer)

Question

A sample of a metal oxide has formula M 0.83 O 1.00. The metal M can exist in two oxidation states +2 and +3. In the sample of M 0.83 O 1.00, the percentage of metal ions existing in +2 oxidation state is %. (nearest integer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/4b416c18b686c6ebdc51ecf558a43c05-.png" /> 2 x+3(0.83-x)=2 x=0.49 % M2+=(0.49/0.83) × 100 =59 %

Q. A sample of a metal oxide has formula $M_{0.83} O_{1.00}$ . The metal $M$ can exist in two oxidation states $+ 2$ and $+ 3$ . In the sample of $M_{0.83} O_{1.00}$ , the percentage of metal ions existing in $+ 2$ oxidation state is___ $%$ . (nearest integer)

$2 x + 3 (0.83 - x) = 2$
$x = 0.49$
$% M^{2 +} = \frac{0.49}{0.83} \times 100$
$= 59%$

Q. A sample of a metal oxide has formula M0.83​O1.00​. The metal M can exist in two oxidation states +2 and +3. In the sample of M0.83​O1.00​, the percentage of metal ions existing in +2 oxidation state is___%. (nearest integer)

2x+3(0.83−x)=2 x=0.49 %M2+=0.830.49​×100 =59%

Q. A sample of a metal oxide has formula $M_{0.83} O_{1.00}$ . The metal $M$ can exist in two oxidation states $+ 2$ and $+ 3$ . In the sample of $M_{0.83} O_{1.00}$ , the percentage of metal ions existing in $+ 2$ oxidation state is___ $%$ . (nearest integer)

$2 x + 3 (0.83 - x) = 2$
$x = 0.49$
$% M^{2 +} = \frac{0.49}{0.83} \times 100$
$= 59%$