A rope of length L and mass M is hanging from a right support. The tension in the rope at a distance the rigid support is

Question

A rope of length L and mass M is hanging from a right support. The tension in the rope at a distance the rigid support is (A) M g (B) ((L-x/L)) M g (C) ((L/L-x)) M g (D) (x/L) M g

Tardigrade Admin · Accepted Answer

Tx=( mass of rope of length L-x)=(M/K)(L-x) g ⇒ Tx=(M g(L-x)/L)

Q. A rope of length $L$ and mass $M$ is hanging from a right support. The tension in the rope at a distance the rigid support is

M g

$(\frac{L - x}{L}) M g$

$(\frac{L}{L - x}) M g$

$\frac{x}{L} M g$

$T_{x} = ($ mass of rope of length $L - x) = \frac{M}{K} (L - x) g$
$\Rightarrow T_{x} = \frac{M g ( L - x )}{L}$

Q. A rope of length L and mass M is hanging from a right support. The tension in the rope at a distance the rigid support is

M g

(LL−x​)Mg

(L−xL​)Mg

Lx​Mg

Tx​=( mass of rope of length L−x)=KM​(L−x)g ⇒Tx​=LMg(L−x)​

Q. A rope of length $L$ and mass $M$ is hanging from a right support. The tension in the rope at a distance the rigid support is

$(\frac{L - x}{L}) M g$

$(\frac{L}{L - x}) M g$

$\frac{x}{L} M g$

$T_{x} = ($ mass of rope of length $L - x) = \frac{M}{K} (L - x) g$
$\Rightarrow T_{x} = \frac{M g ( L - x )}{L}$