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Physics
A rope of length L and mass M is hanging from a right support. The tension in the rope at a distance the rigid support is
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Q. A rope of length $L$ and mass $M$ is hanging from a right support. The tension in the rope at a distance the rigid support is
Laws of Motion
A
M g
20%
B
$\left(\frac{L-x}{L}\right) M g$
47%
C
$\left(\frac{L}{L-x}\right) M g$
15%
D
$\frac{x}{L} M g$
19%
Solution:
$T_{x}=($ mass of rope of length $L-x)=\frac{M}{K}(L-x) g$
$\Rightarrow T_{x}=\frac{M g(L-x)}{L}$