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Q. A rope of length $L$ and mass $M$ is hanging from a right support. The tension in the rope at a distance the rigid support is

Laws of Motion

Solution:

$T_{x}=($ mass of rope of length $L-x)=\frac{M}{K}(L-x) g$
$\Rightarrow T_{x}=\frac{M g(L-x)}{L}$