A rope is wound round a hollow cylinder of mass 5 kg and radius 60 cm. If the rope is pulled with a force of 80 N. What is the angular acceleration of the cylinder?

Question

A rope is wound round a hollow cylinder of mass 5 kg and radius 60 cm. If the rope is pulled with a force of 80 N. What is the angular acceleration of the cylinder? (A) 25 rad / s 2 (B) 26.6 rad / s 2 (C) 30 rad / s 2 (D) 38 rad / s 2

Tardigrade Admin · Accepted Answer

I=M R2=5 ×(0.6)2=5 × 0.36=1.8 kg m 2 Torque =80 × 0.6=48 Nm τ=I α ∴ α=(τ/I)=(48/1.8) =26.6 rad s -2

Q. A rope is wound round a hollow cylinder of mass $5 k g$ and radius $60 c m$ . If the rope is pulled with a force of $80 N$ . What is the angular acceleration of the cylinder?

$25 r a d / s^{2}$

$26.6 r a d / s^{2}$

$30 r a d / s^{2}$

$38 r a d / s^{2}$

$I = M R^{2} = 5 \times (0.6)^{2} = 5 \times 0.36 = 1.8 k g m^{2}$
Torque $= 80 \times 0.6 = 48 N m$
$τ = I α$
$∴ α = \frac{τ}{I} = \frac{48}{1.8}$
$= 26.6 r a d s^{- 2}$

Q. A rope is wound round a hollow cylinder of mass 5kg and radius 60cm. If the rope is pulled with a force of 80N. What is the angular acceleration of the cylinder?

25rad/s2

26.6rad/s2

30rad/s2

38rad/s2