Q.
A rod of length 2.4m and radius 4.6mm carries a negative charge of 4.2×10−7C spread uniformly over it surface. The electric field near the mid-point of the rod, at a point on its surface is
Here, 1=2.4m,r=4.6mm=4.6×10−3mq=4.6×10−7C
Linear charge density, λ=1q=2.4−4.2×10−7=−1.75×10−7Cm−1 Electric field, E=2πε0rλ=2×3.14×8.854×10−12×4.6×10−3−1.75×10−7=−6.67×105NC−1