A rod of fixed length 2 slides along the positive coordinate axes. If it meets the axes at mathrmA( mathrma, 0) and mathrmB(0, mathrm~b), then the value (a+(1/a))2+(b+(1/b))2 can be -

Question

A rod of fixed length 2 slides along the positive coordinate axes. If it meets the axes at mathrmA( mathrma, 0) and mathrmB(0, mathrm~b), then the value (a+(1/a))2+(b+(1/b))2 can be - (A) 7 (B) 8 (C) 9 (D) 10

Tardigrade Admin · Accepted Answer

Correct answer is (c) 9Correct answer is (d) 10

Q. A rod of fixed length 2 slides along the positive coordinate axes. If it meets the axes at A(a,0) and B(0, b), then the value (a+a1​)2+(b+b1​)2 can be -

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Correct answer is (c) 9Correct answer is (d) 10

Q. A rod of fixed length 2 slides along the positive coordinate axes. If it meets the axes at $A (a, 0)$ and $B (0, b)$ , then the value $(a + \frac{1}{a})^{2} + (b + \frac{1}{b})^{2}$ can be -