A river 200 m wide is flowing at a rate of 3.0 m / s. A boat is sailing at a velocity of 15 m / s with respect to the water in a direction perpendicular to the river. How far from the point directly opposite to the starting point does the boat reach on the opposite bank?

Question

A river 200 m wide is flowing at a rate of 3.0 m / s. A boat is sailing at a velocity of 15 m / s with respect to the water in a direction perpendicular to the river. How far from the point directly opposite to the starting point does the boat reach on the opposite bank? (A) 25 m (B) 60 m (C) 40 m (D) 50 m

Tardigrade Admin · Accepted Answer

The given situation is shown in the following figure

Velocity of river,

v_{r} = 3 m s^{- 1}

Velocity of boat,

v_{b} = 15 m s^{- 1}

Width of river

= A B = 200 m

According to question, we have to calculate distance

BC

.
Time taken by boat to cross the river,

t = \frac{A B}{v _{b}} = \frac{200}{15} = \frac{40}{3} s

Since, boat covers horizontal distance

BC

due to it own velocity.
Hence,

BC = v_{r} \times t = 3 \times \frac{40}{3} = 40 m

Q. A river $200 m$ wide is flowing at a rate of $3.0 m / s$ . A boat is sailing at a velocity of $15 m / s$ with respect to the water in a direction perpendicular to the river. How far from the point directly opposite to the starting point does the boat reach on the opposite bank?

$25 m$

$60 m$

$40 m$

$50 m$

Q. A river 200m wide is flowing at a rate of 3.0m/s. A boat is sailing at a velocity of 15m/s with respect to the water in a direction perpendicular to the river. How far from the point directly opposite to the starting point does the boat reach on the opposite bank?

25m

60m

40m

50m

Q. A river $200 m$ wide is flowing at a rate of $3.0 m / s$ . A boat is sailing at a velocity of $15 m / s$ with respect to the water in a direction perpendicular to the river. How far from the point directly opposite to the starting point does the boat reach on the opposite bank?

$25 m$

$60 m$

$40 m$

$50 m$