A ring of charge with radius 0.5 m has 0.002π m gap. If the ring carries a charge of +1 C, the electric field at the centre is

Question

A ring of charge with radius 0.5 m has 0.002π m gap. If the ring carries a charge of +1 C, the electric field at the centre is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-wsoaec1msdqzpxct.jpg" /> (A) 7.5× 107 N C- 1 (B) 7.2× 107 N C- 1 (C) 6.2× 107 N C- 1 (D) 6.5× 107 N C- 1

Tardigrade Admin · Accepted Answer

Approaximate charge on the element opposite to the gap is

Δ q = \frac{Q}{2 π r} (0.002 π)

= \frac{1}{2 π ( 0.5 )} \times \frac{2 π}{1000} = 2 \times (10)^{- 3} C

E = \frac{9 \times 1 0 ^{9} \times 2 \times 1 0 ^{- 3}}{( 0.5 ) ^{2}} = 7.2 \times 1 0^{7} N C^{- 1}

Q. A ring of charge with radius $0.5 m$ has $0.002 π m$ gap. If the ring carries a charge of $+ 1 C,$ the electric field at the centre is

$7.5 \times 1 0^{7} N C^{- 1}$

$7.2 \times 1 0^{7} N C^{- 1}$

$6.2 \times 1 0^{7} N C^{- 1}$

$6.5 \times 1 0^{7} N C^{- 1}$

Approaximate charge on the element opposite to the gap is
$Δ q = \frac{Q}{2 π r} (0.002 π)$
$= \frac{1}{2 π ( 0.5 )} \times \frac{2 π}{1000} = 2 \times (10)^{- 3} C$
$E = \frac{9 \times 1 0 ^{9} \times 2 \times 1 0 ^{- 3}}{( 0.5 ) ^{2}} = 7.2 \times 1 0^{7} N C^{- 1}$

Q. A ring of charge with radius 0.5m has 0.002πm gap. If the ring carries a charge of +1C, the electric field at the centre is

7.5×107NC−1

7.2×107NC−1

6.2×107NC−1

6.5×107NC−1