Q.
A rigid rod of length 2L is acted upon by some forces. All
forces labelled F have the same magnitude. Which cases
have a non-zero net torque acting on the rod about its
centre?
3599
241
System of Particles and Rotational Motion
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Solution:
By sign convention anticlockwise moment (or torque) is taken as position while clockwise moment (or torque) is taken as negative. In case I, net torque about its centre is τ=F×L+F×L=2FL
In case II, net torque about its centre is τ=F×L+F×2L+F×L=25FL
In case III, net torque about its centre is τ=−F×L+F×2L−F×2L+F×L=0