A reversible heat engine converts one-fourth of the heat input into work. When the temperature of the sink is reduced by 52 K, its efficiency is doubled. The temperature in Kelvin of the source will be

Question

A reversible heat engine converts one-fourth of the heat input into work. When the temperature of the sink is reduced by 52 K, its efficiency is doubled. The temperature in Kelvin of the source will be (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

η=(1/4)=1-(T2/T1) (T2/T1)=(3/4) (T2-52/T1)=(1/2)

Q. A reversible heat engine converts one-fourth of the heat input into work. When the temperature of the sink is reduced by $52 K$ , its efficiency is doubled. The temperature in Kelvin of the source will be

$η = \frac{1}{4} = 1 - \frac{T _{2}}{T _{1}}$
$\frac{T _{2}}{T _{1}} = \frac{3}{4}$
$\frac{T _{2} - 52}{T _{1}} = \frac{1}{2}$

Q. A reversible heat engine converts one-fourth of the heat input into work. When the temperature of the sink is reduced by 52K, its efficiency is doubled. The temperature in Kelvin of the source will be

η=41​=1−T1​T2​​ T1​T2​​=43​ T1​T2​−52​=21​

Q. A reversible heat engine converts one-fourth of the heat input into work. When the temperature of the sink is reduced by $52 K$ , its efficiency is doubled. The temperature in Kelvin of the source will be

$η = \frac{1}{4} = 1 - \frac{T _{2}}{T _{1}}$
$\frac{T _{2}}{T _{1}} = \frac{3}{4}$
$\frac{T _{2} - 52}{T _{1}} = \frac{1}{2}$