A reversible cyclic process for an ideal gas is shown below. Here, P, V, and T are pressure, volume and temperature, respectively. The thermodynamic parameters q, w, H and U are heat, work, enthalpy and internal energy, respectively. The correct option(s) is (are)

Question

A reversible cyclic process for an ideal gas is shown below. Here, P, V, and T are pressure, volume and temperature, respectively. The thermodynamic parameters q, w, H and U are heat, work, enthalpy and internal energy, respectively. The correct option(s) is (are) (A) qA C=Δ UB C and WA B=P2(V2-V1) (B) W BC = P 2( V 2- V 1) and H BC =Δ H AC  (C) Δ HC A<Δ UC A and qA C=Δ UB C (D) qB C=Δ HA C and Δ HC A>Δ UC A

Tardigrade Admin · Accepted Answer

AC- Isochoric W =Δ u = n C v ( T 2- T 1) q = OAB - Isothermal W =-2.303 RT log ( V 2/ V 1) q =- WBC - Isobaric; W =- p Δ V =- n R ( T 2- T 1)

Q. A reversible cyclic process for an ideal gas is shown below. Here, $P, V,$ and $T$ are pressure, volume and temperature, respectively. The thermodynamic parameters $q, w, H$ and $U$ are heat, work, enthalpy and internal energy, respectively.
The correct option(s) is (are)

$q_{A C} = Δ U_{BC}$ and $W_{A B} = P_{2} (V_{2} - V_{1})$

$W_{BC} = P_{2} (V_{2} - V_{1})$ and $H_{BC} = Δ H_{A C}$

$Δ H_{C A} < Δ U_{C A}$ and $q_{A C} = Δ U_{BC}$

$q_{BC} = Δ H_{A C}$ and $Δ H_{C A} > Δ U_{C A}$

$A C -$ Isochoric
$W = Δ u = n C_{v} (T_{2} - T_{1})$
$q = O A B -$ Isothermal
$W = - 2.303 RT lo g \frac{V _{2}}{V _{1}}$
$q = - W BC -$ Isobaric;
$W = - p Δ V = - n R (T_{2} - T_{1})$

Q. A reversible cyclic process for an ideal gas is shown below. Here, P,V, and T are pressure, volume and temperature, respectively. The thermodynamic parameters q,w,H and U are heat, work, enthalpy and internal energy, respectively. The correct option(s) is (are)

qAC​=ΔUBC​ and WAB​=P2​(V2​−V1​)

WBC​=P2​(V2​−V1​) and HBC​=ΔHAC​

ΔHCA​<ΔUCA​ and qAC​=ΔUBC​

qBC​=ΔHAC​ and ΔHCA​>ΔUCA​