A resonant AC circuit contains a capacitor of capacitance 10-6F and an inductor of 10-4H The frequency of electrical oscillator will be

Question

A resonant AC circuit contains a capacitor of capacitance 10-6F and an inductor of 10-4H The frequency of electrical oscillator will be (A)  105Hz  (B) 10 Hz (C)  (105/2π )Hz  (D)  (10/2π )Hz

Tardigrade Admin · Accepted Answer

Frequency, v=(1/2π √LC) =(I/2π √10-6× 10-4)=(105/2π )Hz

Q. A resonant AC circuit contains a capacitor of capacitance $10^{- 6} F$ and an inductor of $10^{- 4} H$ The frequency of electrical oscillator will be

$10^{5} Hz$

10 Hz

$\frac{10 ^{5}}{2 π} Hz$

$\frac{10}{2 π} Hz$

Frequency, $v = \frac{1}{2 π L C}$
$= \frac{I}{2 π 10 ^{- 6} \times 10 ^{- 4}} = \frac{10 ^{5}}{2 π} Hz$

Q. A resonant AC circuit contains a capacitor of capacitance 10−6F and an inductor of 10−4H The frequency of electrical oscillator will be

105Hz

10 Hz

2π105​Hz

2π10​Hz

Frequency, v=2πLC​1​ =2π10−6×10−4​I​=2π105​Hz

Q. A resonant AC circuit contains a capacitor of capacitance $10^{- 6} F$ and an inductor of $10^{- 4} H$ The frequency of electrical oscillator will be

$10^{5} Hz$

$\frac{10 ^{5}}{2 π} Hz$

$\frac{10}{2 π} Hz$

Frequency, $v = \frac{1}{2 π L C}$
$= \frac{I}{2 π 10 ^{- 6} \times 10 ^{- 4}} = \frac{10 ^{5}}{2 π} Hz$