A resistor of 10 kΩ having tolerance 10 % is connected in series with another resistor of 20 kΩ having tolerance 20 % . The tolerance of the combination will be approximately

Question

A resistor of 10 kΩ having tolerance 10 % is connected in series with another resistor of 20 kΩ having tolerance 20 % . The tolerance of the combination will be approximately (A) 10 % (B) 13 % (C) 17 % (D) 20 %

Tardigrade Admin · Accepted Answer

Δ Rs=Δ R1+Δ R2=[(10/100) × 10 + (20/100) × 20]kΩ =5kΩ (ÎRs/Rs)× 100=(5/30)× 100=(50/3)=17 %

Q. A resistor of $10 k Ω$ having tolerance $10%$ is connected in series with another resistor of $20 k Ω$ having tolerance $20%$ . The tolerance of the combination will be approximately

$10%$

$13%$

$17%$

$20%$

$Δ R_{s} = Δ R_{1} + Δ R_{2} = [\frac{10}{100} \times 10 + \frac{20}{100} \times 20] k Ω = 5 k Ω$
$\frac{Δ R _{s}}{R _{s}} \times 100 = \frac{5}{30} \times 100 = \frac{50}{3} = 17%$

Q. A resistor of 10kΩ having tolerance 10% is connected in series with another resistor of 20kΩ having tolerance 20% . The tolerance of the combination will be approximately

10%

13%

17%

20%